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进制转化

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进制转化

改进了一下进制转化的代码,每次都有进步

Code
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#include<stdio.h>
#include<string.h>

char result[1000];
static int Name[36]={'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'};

void reverse(char *p)
{
    int len = strlen(p);
    int i = 0;
    int j = len-1;
    char ch;
    while(i<j)
    {
        ch = p[i];
        p[i] = p[j];
        p[j] = ch;
        i++;
        j--;
    }
    return;
}
void conver(int n, int m)  
{
    int signal = 0;
    int i = 0;
    if(n<0)
    {
        n = -n;
        signal = -1;
        i= 1;
    }
    while(n/m!=0)
    {
        result[i++] = Name[n%m];
        n = n/m;
    }
    result[i] = Name[n];
    result[i+1] = 0;
    if(signal==-1)
    {
        result[0] = '-';
        reverse(result+1);
    }
    else
        reverse(result);
    printf("%s\n",result);
}

int main()
{
    int n,m;
    while(~scanf("%d %d",&n,&m))
        conver(n,m);
    return 0;
}

将十进制n转化成m进制的字符串输出 这里还可以进一步的是,将十进制的字符串 void conver(char *n, int m)

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